Question

the sum of two numbers is 100. their difference is 28 . find them​

Answer 1

Answer:

The numbers are 36 and 64 whose difference is 28 and the sum is 100

Step-by-step explanation:

Given :

The sum of two numbers is 100

The difference of two numbers is 28

To Find :

The numbers with sum 100 and difference 28

Solution :

Since the sum of the numbers = 100

and the difference of the two numbers = 28

Let's assume that the numbers are 'x' and 'y'

The according the question the sum of the two numbers = 100

$x+y=100\ \ \ \ \ \ \ \ \ \ \ \ \.........\text{Equation(1)}$

Again the difference of the two numbers is 28

$x-y=28\ \ \ \ \ \ \ \ \ \ \ \ \.........\text{Equation(2)}$

From the equation (2) the value of x = 28 + y

substitute this value in the Equation(1)

$28+y+y=100$

$2y=100-28$

$2y = 72$

$y= 36$

Now substitute y = 36 in the equation (1)

$x+36=100$

$x = 100-36$

$x = 64$

Hence we have calculated that the numbers are 36 and 64 whose difference is 28 and the sum is 100

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Answer 2

Answer:

64 and 36 are the required numbers.

Step-by-step explanation:

Explanation:

Given that, the sum of the two numbers is 100 and their difference is 28.

Let x and y be the two numbers.

Now, the sum of the numbers is 100.

⇒ x + y = 100 ..........(i)

And their difference = 28

⇒ x - y = 28...........(ii)

Step 1:

On solving (i) and (ii) we get,

x + y = 100

x - y = 28  

2x = 128

⇒ x = $\frac{128}{2}$ = 64

Now we put the value of x = 64 in  equation (i)

⇒ x + y = 100

⇒ 64 + y = 100

⇒ y = 100 - 64 = 36

Final answer:

Hence, 64 and 36 are the required numbers.

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