Question

The sum of two numbers is 11. Find the numbers if 2 times one of these numbers exceeds three times the other number by 2​

Answer 1

❍ Given :-

• Sum of two numbers is 11

❍ To Find :-

✏ Condition :-

• Find the numbers if 2 times one of these numbers exceeds three times the other number by 2.

❍ Solution :-

Let one number of x and other be y.

$\mathtt {→x + y = 11}$

$\mathtt {→y = 11 - x}$ → Equation 1

✏ Equation according to condition,

$\mathtt {→2x = 3y + 2}$ → Equation 2

➸ As we got value of y, we will put value of y in this equation,

$\mathtt {→2x = 3(11 - x) + 2}$

$\mathtt {→2x = 33 - 3x + 2}$

$\mathtt {→3x + 2x = 33 + 2}$

$\mathtt {→5x = 35}$

$\mathtt {→x = \frac{35}{5}}$

$→\boxed{\mathtt{x = 7}}$

✏ First number is 7.

Putting value of x in equation 1,

$→\mathtt{y = 11 - x}$

$→\mathtt{y = 11 - 7}$

$→\boxed{\mathtt{y = 4}}$

✏ Second number is 4.

Therefore, the two numbers are 7 and 4 respectively.

Answer 2

Answer:

may this help you a lot.....