Question

The sum of two numbers is 127. One of the numbers is 7 more than half of the other number. Find the numbers.
(this is a chalenge)​

Answer 1

Given: The sum of two numbers is 127 of which first number is 7 more than half of the other number.

Solution:

Let's assume the second number be x.

Therefore,

2nd number = 7 + x/2

Now, according to the question,

First number + second number = 127

x + 7 + x/2 = 127

x + x/2 = 127 - 7

3x/2 = 120

x = 120 * 2/3

x = 80

So first number is 80.

Second number is given by,

7 + x/2

7  + 80/2

7 + 40

47

So second number is 47.

Answer 2

Answer:

80 , 47

Step-by-step explanation:

Sum of numbers = 127

x

y = x/2 + 7

x + x/2 + 7 = 127

2x/2 + x/2 = 127 - 7

3x/2 = 120

3x = 120 × 2

3x = 240

x = 240/3

x = 80

y = 127 - 80

y = 47