Question

the sum of two numbers is 137 and there difference is 43 .find the numbers?​

Answer 1

Step-by-step explanation:

Given: Sum of two numbers is 37 and difference is 43

Let is consider, first number =x and

Second number =y

x+y=137...(1)

x−y=43...(2)

Adding both the equation, we get

2x=180

or x=90

On subtracting (2) from (1)

2y=94

y=47

So,

First number =90 and

Second number =47

Answer 2

QUESTION:-

the sum of two numbers is 137 and there difference is 43 .find the numbers?​

EXPLANATION:-

Let the numbers be x and y respectively

According to given conditions we have,

Their sum=137 .

x+y=137           (eq-1)

Their difference=43

x-y=43             (eq-2)

From eq- and 2 we have

x+y=137

x=137-y

Substitute x=137-y in eq-2

x-y=43

137-y-y=43

137-2y=43

-2y=43-137

-2y=-94

y=(-94)/(-2)

$\boxed{\bf\;y=47}$

So the value of y is 47

Substitute y=47 in eq-1

x+y=137

x+47=137

x=137-47

x=90

So x=47 and y=90