Question

the sum of two numbers is 1600. if 12% of one of the number is equal to 20% of the other .then find the numbers?


Gave me right solution step by step. I will really mark your answer as brainlist. ​

Answer 1

Answer:

Given -

• Sum of two numbers = 1600
• 12% of one number is equal to the 20% of second one.

To find -

• We need to find the numbers

Solution -

Let the one number be x and second number be (1600 - x).

Then,

$\\ \sf \: \dfrac{12}{100} x \: = \dfrac{20}{100} \times (1600 - x) \\ \\ \\ \sf{ \underline{solving \: the \: above \: equation \: we \: get : }} \\ \\ \\ \implies \sf \: 12x = 32000 - 20x \\ \\ \\ \implies \sf \: 12x + 20x = 32000 \\ \\ \\ \implies \sf \: 32x = 32000 \\ \\ \\ \implies \sf \: x = \frac{32000}{32} \\ \\ \\ \implies \sf \green{x = 1000}$

Putting the value of x in (1600 - x) we'll get the second number -

1600 - 1000 = 600

Therefore, the numbers are 1000 and 600.

Answer 2

Step-by-step explanation:

$\bf{\underline{\underline\red{Given:-}}}$

• The sum of two numbers is 1600.

• 12% of one of numbers is equal to 20% of the other.

$\bf{\underline{\underline\blue{To\:Find:-}}}$

• The two numbers.

$\bf{\underline{\underline\green{Solution:-}}}$

As

The sum of two numbers is 1600

Let one of the numbers be x

The other number = 1600 - x

12% of the first number = 12% of x

20% of the second number = 20% of (1600 - x)

Given, they both are equal.

So:-

$\rm \implies12\% \: of \: x = 20\% \: of \: (1600 - x)$

$\rm \implies12\% \: \times \: x = 20\% \: \times \: (1600 - x)$

$\rm \implies \dfrac{12}{100} \: \times \: x = \dfrac{20}{100} \: \times \: (1600 - x)$

$\rm \implies \dfrac{12x}{100} \ = \dfrac{20(1600 - x)}{100}$

$\rm \implies \dfrac{12x}{100} \ = \dfrac{32000 - 20x}{100}$

$\rm \implies {12x}\ = {32000 - 20x}$

$\rm \implies {12x + 20x}\ = {32000 }$

$\rm \implies {32x}\ = {32000 }$

$\rm \implies {x}\ = \dfrac{32000 } {32}$

$\rm \implies {x}\ = {1000 }$

Therefore:-

The first number = x = 1000

The second number = 1600 - x = 1600 - 1000 = 600

$\large\underline {\boxed {\purple{\rm \therefore \: The \: numbers \: are \: 1000 \: and \: 600}}}$