Question

The sum of two numbers is −17. Their difference is 41. Find the numbers.

Answer 1

Answer:

Step-by-step explanation:

a similar question

Let Numbers be x and y respectively.

    We have, x+y= 67 . equation .(1)

              and x-y= 15 .equation .........(2)

            By Adding Eqn. (1) & (2)

        

                    x+y= 67

                    x-y=  15

                 ∴2x=     82

                     ∴x=82/2= 41 

           By Putting x=41 in eqn. (2)

                        41-y=15

                          ∴y=26

Answer 2

Answer: The numbers are 12 and −29.

Step-by-step explanation:

We are looking for two numbers. Let n represent the first number, and let m represent the second number. We are given the sum of the two numbers is −17, so that

n+m=−17

We are also given their difference is 41 so that

n−m=41

The system of equations is

n+m=−17

n−m=41

To solve the system, we use elimination. Since the coefficients of m are opposites, we add the equations to eliminate m and solve for n.

n+m=−17

n−m=41

2n=24

n=12

To solve for m, we can substitute n=12 into either of the original equations. Substituting n=12 into the first equation gives

n+m= -17

12+m= -17

m= -29

The numbers are 12 and −29.