Question

The sum of two numbers is 184. if one-third of the one exceeds one - seventh of the other by 8, find the smaller number?

Answer 1

Answer:

Smaller number = 72

Step-by-step explanation:

Let the first number be x

Let the second number be y

We are given that the sum of two numbers is 184

So,$x+y=184$ --1

Now we are given that one-third of the one exceeds one - seventh of the other by 8

So, A.T.Q

$\frac{x}{3}-\frac{y}{7}=8$

$\frac{7x-3y}{21}=8$

$7x-3y=8 \times 21$

$7x-3y=168$ --2

Now substitute the value of x from 1 in 2

$7(184-y)-3y=168$

$1288-7y-3y=168$

$1288-168=10y$

$1120=10y$

So, y =112

Substitute the value of y in 1

$x+112=184$

$x=184-112$

$x=72$

Hence the smaller number is 72.