the sum of two numbers is 184 one third of one number exceeds one seventh of the other number by 8 find the two numbers
Answers
Answered by
101
Hi ,
let one number = x
second number = 184 - x
according to the problem given,
x /3 - ( 184 -x )/7 = 8
[ 7x - 3(184 - x ) ] /21 = 8
7x - 552 + 3x = 21 × 8
10x = 168 + 552
10x = 720
x = 720 / 10
x = 72
Therefore ,
one number = x = 72
second number = 184 - x
= 184 - 72
= 112
I hope this helps you.
:)
let one number = x
second number = 184 - x
according to the problem given,
x /3 - ( 184 -x )/7 = 8
[ 7x - 3(184 - x ) ] /21 = 8
7x - 552 + 3x = 21 × 8
10x = 168 + 552
10x = 720
x = 720 / 10
x = 72
Therefore ,
one number = x = 72
second number = 184 - x
= 184 - 72
= 112
I hope this helps you.
:)
Answered by
145
Answer:
Step-by-step explanation:
Given :-
The sum of two numbers is 184.
If one-third of the one exceeds one-seventh of the other by 8
To Find :-
The Smaller Number
Solution :-
Let the numbers be x and (184 - x).
According to the Question
⇒ (x/3) - ((184 – x)/7) = 8
⇒ 7x – 3(184 – x) = 168
⇒10x = 720
⇒ x = 720/10
⇒ x = 72.
Therefore, the numbers are 72 and 112.
Hence, smaller number = 72.
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