Question

The sum of two numbers is 184. One-third of one number exceeds oneseventh of the other number by 8. Find the two numbers.

Answer 1

Hey mate,
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Let the first number be x

And the other number will be ( 184 - x )

A/Q,

$\frac{1}{3} \times x = \frac{1}{7} \times (184 - x) + 8$

$= > \frac{x}{3} = \frac{184 - x + 8}{7}$

$= > \frac{x}{3} = \frac{192 - x}{7}$

$= > 7x = 3(192 - x)$

$= > 7x = 576 - 3x$

$= > 10x = 576$

$= > x = 57.6$

The other number = ( 184 - 57.6 ) = 126.4