The sum of two numbers is 2490. If 6.5% of one number is equal to 8.5% of the other,find the numbers
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The sum of two numbers is 2490
let two numbers be x, y
so, x+y = 2490
x = 2490 - y............(1)
If 6.5% of one number is equal to 8.5% of the other
so, 6.5% of x = 8.5% of y
6.5 (2490 - y) = 8.5 y
16185 - 6.5y = 8.5y
16185 = 8.5y + 6.5y
15y = 16185
y = 16185/15
y = 1079
substitute y in (1)
x = 2490 - 1079
x = 1411
The two numbers are x = 1411 and y = 1079
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let two numbers be x, y
so, x+y = 2490
x = 2490 - y............(1)
If 6.5% of one number is equal to 8.5% of the other
so, 6.5% of x = 8.5% of y
6.5 (2490 - y) = 8.5 y
16185 - 6.5y = 8.5y
16185 = 8.5y + 6.5y
15y = 16185
y = 16185/15
y = 1079
substitute y in (1)
x = 2490 - 1079
x = 1411
The two numbers are x = 1411 and y = 1079
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Answer:
sum of two numbers=2490
x+y=2490
6.5x%+8.5x%=2490
15x/100=2490
15x=2490*100
x = 2490*100/15
= 166*100
= 16600
1st number= 6.5%x
= 6.5/100*16600
= 1079
2nd number=8.5%x.
= 8.5/100*16600
= 1411
Step-by-step explanation:
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