Question

The sum of two numbers is 2604 and their HCF is 124. Which is the smaller between them if their difference
is the least possible?​

Answer 1

Step-by-step explanation:

First, I will find the Prime Factorization for each of the three numbers:

First, I will find the Prime Factorization for each of the three numbers:2*2*2*2*3*3 [Prime Factorization of 144]

First, I will find the Prime Factorization for each of the three numbers:2*2*2*2*3*3 [Prime Factorization of 144]2*2*2* 3*3*3 [Prime Factorization of 216]

First, I will find the Prime Factorization for each of the three numbers:2*2*2*2*3*3 [Prime Factorization of 144]2*2*2* 3*3*3 [Prime Factorization of 216]2*2*2*2*3*3*3 [Prime Factorization of 432 (LCM)]

First, I will find the Prime Factorization for each of the three numbers:2*2*2*2*3*3 [Prime Factorization of 144]2*2*2* 3*3*3 [Prime Factorization of 216]2*2*2*2*3*3*3 [Prime Factorization of 432 (LCM)]2*2*2* 3*3 [Prime Factorization of 72(HCF)

First, I will find the Prime Factorization for each of the three numbers:2*2*2*2*3*3 [Prime Factorization of 144]2*2*2* 3*3*3 [Prime Factorization of 216]2*2*2*2*3*3*3 [Prime Factorization of 432 (LCM)]2*2*2* 3*3 [Prime Factorization of 72(HCF)From this configuration, given that the Prime Factorization of the LCM must have factors that are in one or the other or both of the two numbers and the HCF must have factors that are in both numbers. Therefore, the missing number must have four 2's and two 3's.

First, I will find the Prime Factorization for each of the three numbers:2*2*2*2*3*3 [Prime Factorization of 144]2*2*2* 3*3*3 [Prime Factorization of 216]2*2*2*2*3*3*3 [Prime Factorization of 432 (LCM)]2*2*2* 3*3 [Prime Factorization of 72(HCF)From this configuration, given that the Prime Factorization of the LCM must have factors that are in one or the other or both of the two numbers and the HCF must have factors that are in both numbers. Therefore, the missing number must have four 2's and two 3's.2*2*2*2*3*3=144

First, I will find the Prime Factorization for each of the three numbers:2*2*2*2*3*3 [Prime Factorization of 144]2*2*2* 3*3*3 [Prime Factorization of 216]2*2*2*2*3*3*3 [Prime Factorization of 432 (LCM)]2*2*2* 3*3 [Prime Factorization of 72(HCF)From this configuration, given that the Prime Factorization of the LCM must have factors that are in one or the other or both of the two numbers and the HCF must have factors that are in both numbers. Therefore, the missing number must have four 2's and two 3's.2*2*2*2*3*3=144Answer: 144 is the other number.

First, I will find the Prime Factorization for each of the three numbers:2*2*2*2*3*3 [Prime Factorization of 144]2*2*2* 3*3*3 [Prime Factorization of 216]2*2*2*2*3*3*3 [Prime Factorization of 432 (LCM)]2*2*2* 3*3 [Prime Factorization of 72(HCF)From this configuration, given that the Prime Factorization of the LCM must have factors that are in one or the other or both of the two numbers and the HCF must have factors that are in both numbers. Therefore, the missing number must have four 2's and two 3's.2*2*2*2*3*3=144Answer: 144 is the other number.Have A Happy Day:-)

Answer 2

Answer:

1240

Step-by-step explanation:

x + y = 2604

HCF is 124

For difference to be minimum y=x+124 (Assuming y to be larger number)

Then we get

x+x+124=2604

2x=2604-124

2x=2480

x=1240 (minimum number is x)

Hope this helps you