the sum of two numbers is 2x^2-3xy+5y^2. If one number is x^2+2xy-3y^2, find the other
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Sum= 2x²-3xy+5y²
One number is = x²+2xy-3y²
Other number is=
2x²-3xy+5y²
- x²+2xy-3y²
=3x²-5xy+8y²
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