the sum of two numbers is 44 . if one of them exceeds the other by 12. find the both numbers.
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Answered by
2
Let the numbers be a & b. Given,
a + b = 44
b = a + 12
a + a + 12 = 44
2a = 32
a =16
b=28
So the numbers are 16 , 18
Hope this helps
a + b = 44
b = a + 12
a + a + 12 = 44
2a = 32
a =16
b=28
So the numbers are 16 , 18
Hope this helps
psamriddhi12p5foyj:
@chainednomad thank you. i asked my sister and she said it is right.
Answered by
1
a + b= 44
b= 12+44
a+a=12+44
2a = 56
a=56/2
a=28
sho the first number is 28
the other number = 44–28=16
hence, the 2 numbers are 28 and 16.....
b= 12+44
a+a=12+44
2a = 56
a=56/2
a=28
sho the first number is 28
the other number = 44–28=16
hence, the 2 numbers are 28 and 16.....
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