Question

The sum of Two numbers is 48 and their product is 432. Find the number

Answer 1

let the numbers be x and y

As per given data
$x + y = 48$
$xy = 432 \: \: \: \: \: y = \frac{432}{x}$
$\frac{ {x}^{2} + 432 }{x} = 48$
${x }^{2} - 48x + 432 = 0$
$(x - 12)(x - 36) = 0$
$x = 12 \: \: \: 36$
required numbers are 12 and 36

Answer 2

Answer:

let no. are x y

x+y=48

xy=432

y=432/x

x+432/x=48

x2+432/x=48

x2-48x+432=0

(x-12)(x-36)