The sum of two numbers is 48. If the smaller number
is one fifth of the larger number, find the two numbers.
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Step-by-step explanation:
Let the smaller number is =x
And the larger number is=Y
According to equation
X+Y =48 -------------(1)
And
X=1/5×Y
=>5X= Y -------------- (2)
Putting the value of Y in equation (1), we get
X+Y=48
=>X+5X=48
=>6X=48
=>X=8
NOW ,putting the value of X in the equation (2)-
5X=Y
=>5×8=Y
=>40=Y
Therefore,
The smaller number is =8
And the larger number is=40
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