Question

the sum of two numbers is 52. the second number is 10 more than the first. find the number​

Answer 1

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Let n = the larger number, and

Let n - 10 = the smaller number.

Since the sum of these two numbers is 52, we can write the following equation:

n + (n - 10) = 52

n + n - 10 = 52

2n - 10 = 52
2n - 10 + 10 = 52 + 10

2n + 0 = 62

2n = 62

(2n)/2 = 62/2

(2/2)n = 62/2

(1)n = 31

n = 31

Therefore, ...

n - 10 = 31 - 10 = 21

CHECK:
n + (n - 10) = 52
31 + 21 = 52
52 = 52

Therefore, the larger number is 31, and the smaller number is 21.

Answer 2

Answer:

x + x+10 = 52

2x + 10 = 52

2x = 52-10

2x = 42

x = 42/2

x = 21

1st no. = x = 21

2nd no. = 2x = 2*21 = 42

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