the sum of two numbers is 56 and one of them is 8 less than the other.what is the smaller number
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1
Answer:
24
Step-by-step explanation:
Let numbers be x and y
x + y = 56 -> Eq. 1
y = x - 8 -> Eq. 2
Put Eq. 2 in Eq. 1 :
x + (x-8) = 56
2x = 64
x = 32
y = 32 - 8 = 24
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