Question

The sum of two numbers is 64.one of the number is 8 less than the other numbers.find the numbers​

Answer 1

Answer:

The best approach to this problem is to express both numbers in terms of the same variable, such as X.

Let's call the smaller number, X.

This means the larger number would be X+8.

We can then write the problem like this: X+X+8=64

Rearrange the equation and we get: 2X = 56.

Solve for X and we see that X=28.

So our two numbers are 28 and 36.

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Answer 2

$\Huge{\mathscr{\fcolorbox{navy}{orange}{\color{darkblue}{Question?}}}}$

✎ The sum of two numbers is 64. One of the number is 8 less than the other number. Find the numbers.

❥ Given :-

✎ Sum of the two numbers = 64

✎ One of the number is 8 less than the other number.

❥ To find :-

✎ The value of the two numbers.

$\huge\bf\green{Solution\:⤵}$

✔ The two numbers are 36 and 28.

❤ Step-by-step explanation:-

⭐ Let the two numbers be $x$ and $x\:-\:8$ respectively.

As per the question, we have

$➪ \: x \: + \: (x \: - \: 8) \: = \: 64 \\ ➪ \: x \: + \: x\: - 8 \: = \: 64 \\ ➪ \: 2x \: = \: 64\: + \: 8 \\ ➪ \: 2x \: = \: 72 \\ ➪ \: x \: = \: \frac{72}{2} \\ ➪ \: x = \: 36$

❣ Therefore, the two numbers are 36 and 28 respectively.

✎ To verify :-

$➵ \: x \: + \: x \: - 8 \: = \: 64 \\ ➵ \: 36 \: + \:36 \: - \: 8 \: = \:64 \\ ➵ \: 64 \: = \: 64$

♣ L. H. S. = R. H. S.

✔ Hence proved.

$\color{cyan}{Hope\:it\:helps.}$