Question

The sum of two numbers is 70 and their difference is 6. Find these numbers by cross-multiplication method.

Answer 1

Let x and y are two number such that
x + y = 70 and x - y = 6

here we have two linear equations in two variables : x + y = 70 and x - y = 6
we have to solve cross multiplication method,
1.x + 1.y - 70 = 0
1.x + (-1).y - 6 = 0
now, $\bf{\frac{x}{1.(-6)-(-1).(-70)}=\frac{-y}{1.(-6)-1(-70)}=\frac{1}{1.(-1)-1.1}}$

$\bf{\frac{x}{-76}=\frac{-y}{64}=\frac{1}{-2}}$

x/-76 = 1/-2 => x = 76/2 = 38
hence, x = 38

similarly, -y/64 = /1-2 => y =64/2 = 32
hence, y = 32

therefore, two numbers are 38 and 32

Answer 2

x/(-76 ) = y/(-64 ) = 1/( -2 )

x= ( -76 )/( -2 )

x = 38

y/( -64) =1/( -2 )

y = ( -64 )/( -2)

y = 32

Therefore ,

x = 38 , y = 32

I hope this helps you.

:)