Math, asked by devmehta6200, 1 year ago

The sum of two numbers is 72. If one of the number is 6 more than the other, find the
numbers.​

Answers

Answered by narayandhule637
38

Let the two numbers be x and (x+6)

By given condition

x+(x+6) = 72

2x=72-6

2x=66

x=66/2

x=33

(x+6) =33+6

=39

Answered by BrainlyKing5
60

Answer:

\large \underline{\boxed{\mathsf{33\: and \: 39}}}

Step-by-step explanation:

Given :

The sum of two numbers is 72. If one of the number is 6 more than the other.

We need to find the numbers.

Solution

According to Question

Let The >>

First number be = x

Therefore

Second number will be = x + 6

Now its given that sum of the number = 72

That is >

\implies \mathsf{(x) \: +   (x + 6) = 72}

\implies \mathsf{2x + 6 = 72}

\implies \mathsf{2x = 72 - 6}

\implies \mathsf{2x = 66}

\implies \mathsf{x = \dfrac{66}{2} = 33}

Therefore

\implies \mathsf{x = 33}

Now putting value x = 33 in our asumed number format we have

First number = x = 33

And

Second number = x + 6 = 33 + 6 = 39

Therefore Required answer is

\underline{\boxed{\mathsf{33\: and \: 39}}}

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