The sum of two numbers is 9 if the sum of the squares of those numbers is 41 find them
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✨✨ HEY MATE..✨✨
HERE IS YOUR ANSWER....
⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️
SUM = 9..
SUM OF SQUARES = 41..
LET CONSIDER THE TWO NUMBERS AS 4 AND 5.
SUM = 4 + 5 = 9 ✔️✔️✔️...
SUM OF SQUARES = 4^2 + 5^2
= 16 + 25.
= 41 ✔️✔️✔️...
◆ THE TWO NUMBERS ARE 4 and 5...
# HOPE IT HELPS YOU....
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HERE IS YOUR ANSWER....
⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️
SUM = 9..
SUM OF SQUARES = 41..
LET CONSIDER THE TWO NUMBERS AS 4 AND 5.
SUM = 4 + 5 = 9 ✔️✔️✔️...
SUM OF SQUARES = 4^2 + 5^2
= 16 + 25.
= 41 ✔️✔️✔️...
◆ THE TWO NUMBERS ARE 4 and 5...
# HOPE IT HELPS YOU....
....
....
....
....
zainab54321:
Thank you so much
Answered by
29
ᴛʜᴇ ꜰɪʀꜱᴛ ɴᴜᴍʙᴇʀ ʙᴇ x
ᴛʜᴇ ꜱᴇᴄᴏɴᴅ ɴᴜᴍʙᴇʀ=9-x
ᴀᴛq
x²+(9-x)²=41
x²+x²+81-18x=41
2x²-18x+81=41
2x²-18x+81-41=0
2x²-18x+40=0
x²-9x+20=0
x²-5x-4x+20=0
x(x-4)-5(x-4)
(x-5)(x-4)
x=5 ᴏʀ x=4
ᴛʜᴇ ɴᴜᴍʙᴇʀꜱ ᴀʀᴇ 5 ᴀɴᴅ 4
ᴛʜᴇ ꜱᴇᴄᴏɴᴅ ɴᴜᴍʙᴇʀ=9-x
ᴀᴛq
x²+(9-x)²=41
x²+x²+81-18x=41
2x²-18x+81=41
2x²-18x+81-41=0
2x²-18x+40=0
x²-9x+20=0
x²-5x-4x+20=0
x(x-4)-5(x-4)
(x-5)(x-4)
x=5 ᴏʀ x=4
ᴛʜᴇ ɴᴜᴍʙᴇʀꜱ ᴀʀᴇ 5 ᴀɴᴅ 4
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