the sum of two numbers is 90 and the greator number exceeds twice the smaller by 15.Find the numbers
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Let the greater no. be x and the smaller no. be y.
Since there are two variables, we will need two equations which can further be solved by your method of convinence ( Elimination/ Substitution or Cross multiplication)
ATQ,
x+ y= 90 --------- (1)
x- 2y= 15-------- (2)
By using substitution, we get x= 90-y and substituting it in eq. 2
90 - y - 2y = 15
90 -3y = 15
-3y = 15 - 90
-3y = - 75
y= 75/ 3
y= 25
So, the smaller no. is 25 and the greater no. will be x= 90 - 25 = 65
Since there are two variables, we will need two equations which can further be solved by your method of convinence ( Elimination/ Substitution or Cross multiplication)
ATQ,
x+ y= 90 --------- (1)
x- 2y= 15-------- (2)
By using substitution, we get x= 90-y and substituting it in eq. 2
90 - y - 2y = 15
90 -3y = 15
-3y = 15 - 90
-3y = - 75
y= 75/ 3
y= 25
So, the smaller no. is 25 and the greater no. will be x= 90 - 25 = 65
GSAnasuya:
you are wrong
Answered by
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Given that the sum of two numbers is 90.
Let the smaller number x.
Then the larger number will be (90 - x).
Given that greater number exceeds twice the smaller by 15.
(90 - x) = 2x + 15.
90 - x = 2x + 15
90 = 3x + 15
3x = 75
x = 25.
If the smaller number is 25 then the larger number will be 90 - x = 90 - 25 = 65
The numbers are 25 and 65.
Let the smaller number x.
Then the larger number will be (90 - x).
Given that greater number exceeds twice the smaller by 15.
(90 - x) = 2x + 15.
90 - x = 2x + 15
90 = 3x + 15
3x = 75
x = 25.
If the smaller number is 25 then the larger number will be 90 - x = 90 - 25 = 65
The numbers are 25 and 65.
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