The sum of two numbers is 95 if one exceeds the other by 15 the smaller one is what
(A)40
(B)35
(C)45
(D)55
Answers
Answered by
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Let the first number be x
second number be (x+15) // one exceed other by 15 //
sum of the number is given by x+(x+15) = 95
x+x+15=95
2x+15 = 95
2x =95-15
2x = 80
x=80/2
x =40
first number x=40, second number x+15 = 40+15= 55
The numbers are 40 and 55.
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Answered by
0
40 is the answer of this question
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