Question

The sum of two numbers is 95. If one exceeds the other by 3. Find the other number.

Don't spam!!

Answer 1

Step-by-step explanation:

Given :

• Sum of two numbers is 95.
• One number exceeds the other by 3.

To Find :

• The other number

Solution :

$\sf{Here \: we \: are \: using \: the \: concept \: of \: linear \: equations \: in \: one \: variable.}$

$\pink{ \bf{Let : }}$

• Let one number be y.
• Other number = y + 3

✠ According to the question,

$\displaystyle{ \sf{ \leadsto \: y + (y + 3) = 95}}$

$\displaystyle{ \sf{ \leadsto \: 2y + 3 = 95}}$

$\displaystyle{ \sf{ \leadsto \: 2y = 95 - 3}}$

• Transporting 3 to R. H. S.

$\displaystyle{ \sf{ \leadsto \: 2y = 92}}$

$\displaystyle{ \sf{ \leadsto \: y = \cancel{\frac{92}{2} }}}$

$\displaystyle{ \sf{ \leadsto \: y = 46}}$

So,

Value of y is 46.

________________________

$\tt{Number \: = 46}$

$\tt{Other \: number \: = y + 3 = 46 + 3 = \pink{49}}$

$\underline{\therefore \tt{ \: 46 \: and \: 49 \: are \: the \: two \: required \: numbers.}}$

Verification :

$\displaystyle{ \sf{ \implies \: y + (y + 3) = 95}}$

$\displaystyle{ \sf{ \implies \: 46 + (46 + 3) = 95}}$

$\displaystyle{ \sf{ \implies \: 46 + 49 = 95}}$

$\displaystyle{ \sf{ \implies \:95 = 95 }}$

$\displaystyle{ \sf{ \implies \:L.H.S.= R. H. S. }}$

Hence, Verified!

Answer 2

Let 1st number is x

Since,

One exceeds the other by 3

Thus,

2nd number is x+3

According to question,

→ x + (x+3) = 95

→ 2x = 95 – 3

→ 2x = 92

→ x = 46

So,

x+3 = 46 +3 = 49

Hence,

The numbers are 46 and 49.

$@vikram$