Question

the sum of two numbers is equal to 80 and the greater number exceeds thrice the smaller number by 11 ..Then find the number ​

Answer 1

Step-by-step explanation:

3x + 11=80

3x=80-11

3x=69

x=69÷3

x=23

3x=3×23=69

69+11=80

the greater no is 69 and smaller is 11 hope it helps

Answer 2

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Let the number be x

Then greater number = 2x + 11

Sum of two numbers = 80

x + 2 + 11 = 80

3x = 80 - 11

3x = 69

x = 23

Hence, smaller number = 23

Greater number = 2 × 23 + 11 = 57