Question

The sum of two odd numbers is 80 and their difference is 6.
Work out these numbers.

Answer 1

Answer:

The answer is x=43,y=37

Answer 2

Let the two numbers be (2m + 1) and (2m + 1) + 6.

By the given conditions,

sum of the numbers = 80

>> (2m + 1) + (2m + 1) + 6 = 80

or, 2m + 1 + 2m + 1 + 6 = 80

or, 4m + 8 = 80

or, 4m = 72

or, m = 18

Therefore the two odd numbers are

2 * 18 + 1 and (2 * 18 + 1) + 6

i.e., 36 + 1 and 36 + 1 + 6

i.e., 37 and 43

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