the sum of two opposite angles of a parallelogram is 140 degree find angles of the parallelogram.
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let the parallelogram be ABCD
in a parallelogram opposite angles are equal
so the sum of one of the opposite angle is 140°
let the opposite angles be
angle A & angle C
then,
angle A = angle C
angle A +angle C=140°
angle C can write as angle A
so,
angle A + angle A=140°
2(angle A )=140°
angle A =140°/2
=70°
angle A = angle C
angle C =70°
in a parallelogram adjacent angle sum = 180°
so,
angle A + angle D=180°
angle D=180°-70°
angle D=110°
opposite angles are equal
angle D = angle B
angle B=110°
now,
the angles are
angle A=70°
angle B=110°
angle C=70°
angle D=110°
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