the sum of two opposite angles of a parallelogram is 140 degree.find all its angles.
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let the four angles of parallelogram be a,b,c,d
since
the opposite angles of the parallelogram are equal i.e a. =c. &. b = d
therefore
a+b = 140
a+ a= 140
2a. = 140
a = 70°
b= 140 - 70
. = 70
therefore
b.+ c. = 360 - 140. =120
b+ b= 120
2 b= 120
b = 60°
c = 120 -60= 60°
since
the opposite angles of the parallelogram are equal i.e a. =c. &. b = d
therefore
a+b = 140
a+ a= 140
2a. = 140
a = 70°
b= 140 - 70
. = 70
therefore
b.+ c. = 360 - 140. =120
b+ b= 120
2 b= 120
b = 60°
c = 120 -60= 60°
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