the sum of two quantities is 13a³+ 5a² - 4a + 1 and one of them is 3a³+ 2a² - a + 2. Find the other
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let other is f(a)
then
according to question,
f(a) + 3a³ +2a² -a +2 = 13a³ +5a²-4a +1
f(a) = (13a³ +5a² -4a +1)-( 3a³ +2a² -a +2)
=(13-3)a³ +(5-2)a² +(-4+1)a +(1-2)
=10a³ +3a² -3a -1
then
according to question,
f(a) + 3a³ +2a² -a +2 = 13a³ +5a²-4a +1
f(a) = (13a³ +5a² -4a +1)-( 3a³ +2a² -a +2)
=(13-3)a³ +(5-2)a² +(-4+1)a +(1-2)
=10a³ +3a² -3a -1
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