Question

the sum of two rational number is -2/5+9 if one of them is 3/10 find the other​

Answer 1

Answer: 83/10

Step-by-step explanation:let , another number be x

                                so,x+3/10=  -2/5+9

                      x +3/10 = -2+45/5

                    x+3/10 =43/5

                        x= 43/5-3/10  again taking l c m,

              x=43×2 -3/10

                  x=86 -3/10 =83/10

Answer 2

$\Huge{\boxed{Solution}}$

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Given :

Sum of two rational

number is $\dfrac{-2}{5}+9$.

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One of the nuber is $\dfrac{3}{10}$

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To find :

Other number.

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Let the :

Other number be 'x'

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According to question we

have to find other number.

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$\implies x+\dfrac{3}{10}=\dfrac{-2}{5}+9\\\\\\\implies x+\dfrac{3}{10}=\dfrac{-2}{5}+\dfrac{9}{1}\\\\\\\implies x+\dfrac{3}{10}=\dfrac{-2+45}{5}$

$\\\\\\\implies x+\dfrac{3}{10}=\dfrac{43}{5}\\\\\\\implies x=\dfrac{43}{5}-\dfrac{3}{10}\\\\\\\implies x=\dfrac{86-3}{10}\\\\\\\implies x=\dfrac{83}{10}$

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$\Huge{\boxed{x=\dfrac{83}{10}}}$

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$\Huge{\underline{\underline{Verification}}}$

$\implies x+\dfrac{3}{10}=\dfrac{-2}{5}+9\\\\\\\implies\dfrac{83}{10}+\dfrac{3}{10}=\dfrac{-2}{5}+9\\\\\\\implies\dfrac{86}{10}=\dfrac{-2+45}{5}$

$\\\\\\\implies\dfrac{86}{10}=\dfrac{43}{5}\\\\\\\implies\dfrac{43}{5}=\dfrac{43}{5}$

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Here' L.H.S = R.H.S

Hence it is verified.

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Therefore other number

is 83/10