Question

The sum of two rational numbers is 4/9 if one number is -3/11 find the other
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Answer 1

Question ::-

The sum of two rational numbers is 4/9 if one number is -3/11 find the other ?

Given ::-

• Sum of two rational numbers is $\dfrac{4}{9}$

• One of them is $\dfrac{-3}{11}$

To find ::-

• Another rational number.

Solution ::-

Let the other number be g

$➠$ $\dfrac{-3}{11}$ + g = $\dfrac{4}{9}$

$➠$ g = $\dfrac{4}{9}$ - $(\dfrac{-3}{11})$

$➠$ g = $\dfrac{44 - (-27)}{99}$

$➠$ g = $\dfrac{44 + 27)}{99}$

$➠$ g = $\dfrac{44 - (-27)}{99}$

$➠$ g = $\dfrac{71}{99}$

___________

Let's varify it ::-

= $\dfrac{-3}{11}$ + $\dfrac{71}{99}$ = $\dfrac{4}{9}$

= $\dfrac{-27 + 71}{99}$ = $\dfrac{4}{9}$

= $\dfrac{44}{99}$ = $\dfrac{4}{9}$

= $\dfrac{\cancel{44}}{\cancel{99}}$

= $\dfrac{4}{9}$

Hence , L.H.S = R.H.S

Answer 2

$\huge\mathtt\red{ꪖꪀs᭙ᴇʀ}$

Given ::-

Sum of two rational numbers is$\dfrac{4}{9}94$

One of them is $\dfrac{-3}{11}11−3$

Solution ::-

Let the other number be g

➠ $\dfrac{-3}{11}11−3 + g = \dfrac{4}{9}94$

➠$g = \dfrac{4}{9}94 - (\dfrac{-3}{11})(11−3)$

➠ $g = \dfrac{44 - (-27)}{99}9944−(−27)$

➠$g = \dfrac{44 + 27)}{99}9944+27)$

➠ $g = \dfrac{44 - (-27)}{99}9944−(−27)$

➠ $g = \dfrac{71}{99}9971$

Verification:-

$−3 + \dfrac{71}{99}9971 = \dfrac{4}{9}94$

$= \dfrac{-27 + 71}{99}99−27+71 = \dfrac{4}{9}94$

$= \dfrac{44}{99}9944 = \dfrac{4}{9}94$

$= \dfrac{\cancel{44}}{\cancel{99}}9944$

$= \dfrac{4}{9}94$

Hence , L.H.S = R.H.S