the sum of two roots of a quadratic equation is 5 and sum of their cubes is 35, find the equation
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A+B=5
A^3 +B^3=35
A^3+B^3=(A+B)^3-3ab( a+ b)
35=125-3ab*5
-90=15ab
ab=6
A^3 +B^3=35
A^3+B^3=(A+B)^3-3ab( a+ b)
35=125-3ab*5
-90=15ab
ab=6
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