Question

the sum of zeroes of 2x^2-3x+y

Answer 1

$\huge \red{ \boxed{ \boxed{ \bf \color{yellow}{ \frac{3}{2} } = \color{cyan}{1.5}}}}$

Step-by-step explanation:

QUESTION :-

Find the sum of zeroes of 2x² - 3x + y.

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SOLUTION :-

2x² - 3x + y

In the standard form of quadratic equation (ax² + bx + c) , here

• a = 2....[coefficient of x²]
• b = - 3....[coefficient of x]
• c = y

For any quadratic equation,

Sum of zeroes =

$\bf = - \frac{b}{a} = - \frac{coefficient \: of \: {x}^{2} }{coefficient \: of \: x}$

So here,

Sum of zeroes will be -

$\bf = - \frac{ - 3}{2} \\ \\ = \bf \red{ \large \frac{3}{2} = 1.5}$

Hence sum of zeroes = 3/2 or 1.5.

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Hope it helps.

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