Question

the sum of zeros of the polynomial 3x2+3x-18​

Answer 1

Answer:

-1

Step-by-step explanation:

3x2+3x-18

Sum of zeroes=-b/a

α+β=-b/a

put values in given formula,we get

α+β=-3/3

= -1

Hence, the sum of zeroes is -1.

Answer 2

The sum of zeros of the polynomial 3x² + 3x - 18 is - 1

Given :

The polynomial 3x² + 3x - 18

To find :

The sum of zeros of the polynomial 3x² + 3x - 18

Concept :

$\sf{If \: \alpha \: and \: \beta \: are \: zeroes \: of \: a \: quadratic \: polynomial }$$\sf{p(x) = a {x}^{2} + bx + c }$

Then ,

$\displaystyle \sf{Sum \: of \: the \: zeroes = \alpha + \beta = - \frac{b}{a} }$

$\displaystyle \sf{Product \: of \: the \: zeroes = \alpha \beta = \frac{c}{a} }$

Solution :

Step 1 of 2 :

Write down the given polynomial

Here the given polynomial is 3x² + 3x - 18

Step 2 of 2 :

Find Sum of the zeroes

The given polynomial is 3x² + 3x - 18

Now comparing with the general polynomial ax² + bx + c we get a = 3 , b = 3 , c = - 18

Hence the sum of the zeroes of the polynomial

$\displaystyle \sf{ = - \frac{b}{a} }$

$\displaystyle \sf{= - \frac{3}{3} }$

$= - 1$

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