the sum of zeros of x square + 2 X + 3 k and the product is equal then what is the value of k
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sum of zeroes=-b/a
product =c/a
.•.-b/a=c/a
-b=c
-2=3k
k=-2/3
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Let the 2 zeroes of the polynomial x^2+2x+3k be alpha and beta.
>a=1,b=2,c=3k
Sum of the zeroes = alpha+beta
= -b/a = -2
Product of the zeroes=alpha*beta
=c/a = 3k
Given, alpha + beta= alpha*beta
=. -2=3k
==> K= -2/3
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