The. Sum ofn terms of two A.P are in ratio( 7n+1) :(4n+27) find the ratio their 11th terms
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given ,
Sn/S'n =(7n + 1)/(4n + 27)
=n/2 {2. (8/2)+(n-1) 7}/n/2 {2(31/2)+(n-1)4}
hence ,
Tn/Tn={4 +(n-1) 7}/{31/2 + (n-1)4}
=(14n - 6)/(8n +23)
put n=11
T11 /T'11 =(14 x 11 -6 )/(8 x 11 +23)
=(148)/(111)
Sn/S'n =(7n + 1)/(4n + 27)
=n/2 {2. (8/2)+(n-1) 7}/n/2 {2(31/2)+(n-1)4}
hence ,
Tn/Tn={4 +(n-1) 7}/{31/2 + (n-1)4}
=(14n - 6)/(8n +23)
put n=11
T11 /T'11 =(14 x 11 -6 )/(8 x 11 +23)
=(148)/(111)
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