The sum og first n odd natural no is 2n_1 2n+1 n^_1 n^
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Answer: n²
Step-by-step explanation:
The odd numbers are in AP.
1, 3, 5,...
a = 1
d = 3 - 1 = 2
a_n = dn + a - d = 2n + 1 - 2 = 2n - 1
S_n = n/2[a + a_n] = n/2[1 + 2n - 1] = n/2 × 2n = 2n² / 2 = n²
Thank you.
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