The sum required to earn a monthly interest of ` 1,200 at 18% per annum SI is
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Answered by
6
p = I *100/ r*t
p = (1200*100)/(18*1/12)
p = 120000*12 / 18
p = 40000 rs
p = (1200*100)/(18*1/12)
p = 120000*12 / 18
p = 40000 rs
Answered by
9
Answer:
80,000
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