Question

the sum to 101 terms of an AP is 1212 then the middle term is

Answer 1

I hope you will be able to understand

Answer 2

The middle term is 12.

Step-by-step explanation:

Given:

Here, $S_{101}=1212$      [1]

We know that,

$S_n=\frac{n}{2} (a+l)$

$S_{101}=\frac{101}{2} (a+l)$

1212 = $\frac{101}{2} (a+l)$                   [from 1]

$a+l= \frac{1212\times2}{101}$

$a+l= 12\times2$

a+l = 24

Also, middle term =$\frac{a+l}{2}$

                              = $\frac{24}{2}$

                              = 12