Question

the sum to n terms of an A.P. is n^2.Find the common difference
$the \: sum \: to \: n \: terms \: of \: an \: ap \: is \: {n}^{2}.find \: the \: common \: difference.$

Answer 1

$sum = \frac{n}{2} (a + last \: term)$
${n}^{2} = \frac{n}{2} (a + n)$
$2 {n}^{2} = an \: + {n}^{2}$
${n}^{2} = a$
tn=a+(n-1)d
$n = {n}^{2} + (n - 1)d$
$\frac{n - {n}^{2} }{n - 1} = d$



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