the sumof ages of father and son is 52 years. five years ago, the age of the father was 5 times the age of the son.find their present age . solve with one variable
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shiv3365:
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age of son = x
age of father = 5x
five years after
(x+5)+(5x+5) = 52
6x + 10 = 52
6x = 52-10
6x = 42
x = 42/6
x = 7
present age
of son = 7+5 = 12
of father = 5×7+5
= 40
Proof:
40+12 = 52
age of father = 5x
five years after
(x+5)+(5x+5) = 52
6x + 10 = 52
6x = 52-10
6x = 42
x = 42/6
x = 7
present age
of son = 7+5 = 12
of father = 5×7+5
= 40
Proof:
40+12 = 52
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