Question

The sun of four consecutive numbers in an ap is 32 and the ratio of the product of the last and the first term to the product of the 2 middle term is 7:15

Answer 1

let the terms be

a-3d,a-d,a+d,a+3d

1-3d+a-d+a+d+a+3d=32

4a=32

a=8

a²-9d²/a²-d²=7/15

64-9d²/64-d²=7/15

15(64-9d²)=7(64-d²)

128d² = 512

d² = 512/128

d² = 4

d = 2

Four consecutive numbers are 2, 6, 10 and 14