Math, asked by komalin, 1 year ago

The surface area of 3D shapes
Find the height of a cylinder whose radius is 7 cm and the total surface
area is 968 sq.cm.

Answers

Answered by Anonymous
1

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Radius = 7 cm

Total surface area = 968

 = 2\pi r \: (r + h) = 968 \\  = 2 \times  \frac{22}{</u><u>\cancel</u><u>7}  \times </u><u>\cancel</u><u>7(7 + h) = 968 \\  = 44(7 + h) = 968 \\  = 7 + h =  \frac{</u><u>\cance</u><u>l</u><u>9</u><u>\cancel</u><u>6</u><u>\cancel</u><u>8}{</u><u>\cancel</u><u>4</u><u>\cancel</u><u>4}  = </u><u>\cancel</u><u>2</u><u>\cancel</u><u>2 = </u><u>\cancel</u><u>4</u><u>\cancel</u><u>8</u><u>\cancel</u><u>4 = 22 \\  = 7 + h = 22 \\  = </u><u>H</u><u>eight = 22 \\  = </u><u>H</u><u>e</u><u>ight = 22 - 7 \\  = </u><u>H</u><u>eight = 15

The height of cyclinder = 15 cm

Answered by ravindrac8
2

Step-by-step explanation:

total surface area of cylinder=2πr(r+h)

968=2×3.14×7(7+h)

968=2×3.14×49h 968=6.28×49h 968-6.28=7h. 961.72=7h

h=961.72/7

h= 138.2457142857....….

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