the surface area of a cube is equal to the sum of the surface area of the Other cube whose edge 3 cm 4 cm and 12 cm find the age of the first cube
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surface area of cube
![6 {a}^{2} 6 {a}^{2}](https://tex.z-dn.net/?f=6+%7Ba%7D%5E%7B2%7D+)
S.A of 1st cube 6×9=54
" " 2nd. " "=6×16=96
3rd. =6×144=864
So acc to question 54+96+864 =1014
![6 {a}^{2} = 1014 \\ 6 {a}^{2} = 1014 \\](https://tex.z-dn.net/?f=6+%7Ba%7D%5E%7B2%7D++%3D+1014+%5C%5C+)
a=13cn
S.A of 1st cube 6×9=54
" " 2nd. " "=6×16=96
3rd. =6×144=864
So acc to question 54+96+864 =1014
a=13cn
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