The surface area of a cube whose edge is 21 cm
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Answered by
3
Answer:
surface area = 6a^2
a=21cm
6×21^2 = 2646cm2
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..Question..
Find the surface area of a cube whose edge is 21 cm.
..Answer..
♧︎︎︎ Given ,
ㅤㅤㅤㅤ➪ side of the cube = 21 cm
ㅤㅤㅤㅤ➪ side of the cube = a ----- ( 1 )
•°• Surface area of the cube ☞︎︎︎
ㅤㅤ➪ 6 a ²
ㅤㅤ➪ 6 × ( 21 )² [ from ( 1 ) ]
ㅤㅤ➪ 6 × ( 20 + 1 )²
ㅤㅤ➪ 6 × ( 20² + 2×20×1 + 1² )
ㅤㅤ➪ 6 × ( 400 + 40 + 1 )
ㅤㅤ➪ ( 6 × 400 ) + ( 6 × 41 )
ㅤㅤ➪ 2400 + 246
ㅤㅤ➪ 2646 ㅤㅤㅤㅤAns....
•°• Surface area of the cube = 2646 cm²
_____________________
Give a look here ,
☯︎ C.S.A of Cylinder
ㅤㅤ➪ 2 π r h
☯︎ Total Surface area of Cylinder
ㅤㅤ➪ 2 π r ( r + h )
☯︎ Circumference of circle
ㅤㅤ➪ 2 π r
☯︎ Area of square
ㅤㅤ➪ π r²
☯︎ perimeter of square
ㅤㅤ➪ 4 s
☯︎ Area of square
ㅤㅤ➪ s²
☯︎ Perimeter of rectangle
ㅤㅤ➪ 2 ( l + b )
☯︎ Area of Rectangle
ㅤㅤ➪ l × b
ㅤㅤㅤ꧁ ʙʀᴀɪɴʟʏ×ᴋɪᴋɪ ꧂
ㅤㅤ
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