The surface area of concentrator type solar heater is 5m2. It can reflect 80% of solar radiation incident while it absorbs the rest. Calculate energy concentrated by heaters as it focus in 2 hours if solar energy was delivered to it at the rate of 0.4 kJ/m2s
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It reflects 80% of the radiation incident on it. Calculate the enegry concentrated by the heater in 1 hour if the solar energy were delivered to it at the rate of 0.66kW/m2. Solution : Energy concentrated =(80/100)(0.66kW/m2)(5m2)(1×60×60s)=9504kJ.13-Jun-2020
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Energy concentrated = Reflecting percentage of energy x Surface area x Time x Rate of solar energy delivered
= $\frac{8}{{100}}$ x 5 x (2 x 60 x 60) x 0.4 x $10^{3}$
= 11520 x $10^{3}$J
=11.52 x $10^{6}$ J
= 11.52 MJ [ $10^{3}$ J = 1MJ]
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