Question

The surface area of cuboid-shaped box having length=80 cm, breadth=40cm and height=20cm is: a. 11200 sq.cm b. 13000 sq.cm c. 13400 sq.cm d. 12000 sq.cm

Answer 1

Given :-

Length of the cuboid-shaped box = 80 cm

Breadth of the cuboid-shaped box = 40 cm

Height of the cuboid-shaped box = 20 cm

To Find :-

The surface area of cuboid-shaped box.

Analysis :-

We are given with all the three dimensions.

Substitute the values in the formula of TSA and find the surface area.

Solution :-

We know that,

• l = Length
• b = Breadth
• h = Height

By the formula,

$\sf \underline{\boxed{\sf Total \ surface \ area= 2(lb + bh + hl) }}$

Given that,

Length (l) = 80 cm

Breadth (b) = 40 cm

Height (h) = 20 cm

Substituting their values,

$\sf =2[(80)(40)+(40)(20)+(20)(80)]$

$\sf = 2(3200+800+1600)$

$\sf =2(5600)$

$\sf =11200 \ cm^{2}$

Therefore, the surface area of cuboid-shaped box is 11200 cm².

Answer 2

Given :-

Length of the cuboid-shaped box = 80 cm

Breadth of the cuboid-shaped box = 40

cm Height of the cuboid-shaped box = 20 cm

To Find :-

The surface area of cuboid-shaped box.

Analysis :

We are given with all the three dimensions.

Substitute values in the formula of TSA and find the surface area.

Solution :-

We know that,

• |= Length .

b = Breadth

h = Height

By the formula,

Total surface area = 2(lb + bh + hl)

Given that,

Length (I) = 80 cm

Breadth (b) = 40 cm =

Height (h) = 20 cm

Substituting their values,

= 2[(80)(40) + (40)(20) + (20)(80)]

= 2(3200 + 800 + 1600)

= 2(5600)

11200 cm

Therefore, the surface area of cuboid shaped box is 11200 cm²