The surface tension of radius 0.1 cm is broken into 27 droplets of the same size. Find the work done if the surface tension of Mercury is 540 dyne/cm
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F = T × effective length = T × 2 l = 0.025 × 2 × 4 × 10-2 = 0.002 N. In this case, the ..A drop of mercury of radius 0.1 cm is broken into 8 droplets of the same size. Find the work done if the surface tension of mercury is 540 dyne/cm. Solution . A mercury drop of radius 0.1 cm breaks up into 27 small droplets.
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