Physics, asked by mitrajit6422, 10 months ago

The surface tension of the water is 72 dyne cm^-1. Express it in SI unit.

Answers

Answered by rr7172283

0

Explanation:

1 dyne = ( gm.cm/sec^2) ÷ cm=( 1/1000×1/100) kg. mtrs /sec^2 ÷ (1/100) mtrs. = (10^-5 newtons) ÷10^-2 mtrs.

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