Question

The system of equations 2x + ky = 11 and 5x -
7y = 5 has no solution if the value of k is
A 13/5
B-13/5
C-14/5
D-16/5​

Answer 1

Answer:

The equations are 2x+ky=11 and 5x−7y=5

or 2x+ky−11=0 and 5x−7y−5=0

They will have no solution if

a

2

a

1

=

b

2

b

1



=

c

2

c

1

.

Here a

1

=2,a

2

=5,b

1

=k,b

2

=−7,c

1

=−11,c

2

=−5

∴

a

2

a

1

=

5

2

,

b

2

b

1

=

−7

k

,

c

2

c

1

=

−5

−11

=

5

11

∴

−7

k

=

5

2

⟹k=

5

−14

Also the first two ratios



=

c

2

c

1

∴k=

5

−14

Hence, the answer is

5

−14